How do you find the limit of #1/t - 1/(t^2+t) # as t approaches 0?

Question

27830 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-14T14:34:08

#" The Lim."=1#.

The Limit#=lim_(trarr0){1/t-1/(t^2+t)}#

#=lim_(trarr0){1/t-1/(t(t+1))}#

#=lim_(trarr0){(t+1-1)/(t(t+1))}#

#=lim_(trarr0)(cancelt/(cancelt(t+1)))#

#=lim_(trarr0)1/(t+1)#

#=1/(0+1)#.

#:." The Lim."=1#.