How do you find the limit of $2 x + 5$ $2x+5$ as $x \to 7^{-}$ $x->7^-$ ?

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Answer 1 · 2016-10-27T13:35:14

$lim_(x->7^-)(2x+5) =19$

$2x+5$ is continuous; so

So,
$lim_(x->7^-)(2x+5) = lim_(x->7^+)(2x+5) = lim_(x->7)(2x+5)$

Hence, $lim_(x->7^-)(2x+5) =2(7)+5=19$

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