Question

How do you find the limit of `2x+5` as `x->7^-`?

Answer 1

`lim_(x->7^-)(2x+5) =19`

Explanation:

`2x+5` is continuous; so

So,
`lim_(x->7^-)(2x+5) = lim_(x->7^+)(2x+5) = lim_(x->7)(2x+5)`

Hence, `lim_(x->7^-)(2x+5) =2(7)+5=19`