Question

How do you find the limit of `2x+5` as `x->-oo`?

Answer 1

`lim_(x rarr -oo) (2x+5)` does not exist

Explanation:

As

`x rarr -oo => 3x rarr -oo`
`" " => 2x+5 rarr -oo`

Hence:

`2x+5` is unbounded as `x rarr -oo`

And so,

`lim_(x rarr -oo) (2x+5)` does not exist