Question

How do you find the limit of `((8 + h)^2 - 64) / h` as h approaches 0?

Answer 1

`lim_(h->0) f(h) = 16`

Explanation:

Given:`" "f(h) = ((8+h)^2-64)/h`

Expanding the brackets.

`(h^2+16h+64-64)/h`

`h^2/h+16h/h`

`h+16`

`=> lim_(h->0) h + lim_(h->0) 16" " =" " 0+16" "=" "16`