How do you find the limit of #cosx# as #x->(5pi)/3#?
1 Answer
Jun 23, 2017
Explanation:
The function
#lim_(xrarr5pi//3)cosx=cos((5pi)/3)=cos(pi/3)=1/2#
The function
#lim_(xrarr5pi//3)cosx=cos((5pi)/3)=cos(pi/3)=1/2#