Question

How do you find the limit of `e^(1/x)` as x approaches `0^-`?

Answer 1

0

Explanation:

`lim_{x to 0^-} e^(1/x)`

`= e ^ (lim_{x to 0^-} 1/x)` because `f(u) = e^u` is a continuous function including through the limit

and `lim_{x to 0^-} 1/x = - oo`

so `lim_{x to 0^-} e^(1/x) = e^(- oo) = 1/ e^( oo) = 0`