Question

How do you find the Limit of `ln(n)/ (ln(n))^2` as n approaches infinity?

Answer 1

`lim_(n->oo) lnn/(lnn)^2 =0`

Explanation:

`lnn/(lnn)^2 = lnn/(lnn xx lnn)`

`= cancel(lnn)/(cancel(lnn) lnn) = 1/lnn`

`:. lim_(n->oo) lnn/(lnn)^2 = lim_(n->oo) 1/lnn -> 1/oo`

`= 0`