Question

How do you find the limit of `ln(x−3)/(x−5)` as x approaches infinity?

Answer 1

`= 0`

Explanation:

This is `oo/oo` indeterminate so we can use LHopital's rule

`lim_(x to oo) ln(x−3)/(x−5)`

`= lim_(x to oo) (1/(x−3))/(1)`

`= lim_(x to oo) 1/(x−3)`

`= 0`