Question

How do you find the limit of `(x^5+3)/(x^2+4)` as `x->oo`?

Answer 1

`oo`

Explanation:

`(x^5+3)/(x^2+4)`

Divide by `x^2`

`(x^5/x^2+3/x^2)/(x^2/x^2+4/x^2)=(x^3/1+3/x^2)/(1+4/x^2)`

as `x->oo` , `(x^3/1+3/x^2)/(1+4/x^2)=(oo+0)/(1+0)->oo`

`:.`

`lim_(x->oo)((x^5+3)/(x^2+4))=oo`