Question

How do you find the local max and min for `f(x) = 1 - sqrt(x)`?

Answer 1

Local maximum is `1` (at `x=0`).

Explanation:

`f'(x) = -1/(2sqrtx)`

`f'(x)` is never `0` and is undefined at `x=0` which is int he domain of `f`. So `0` is a critical number.

`f'` is not defined left of `0` and is negative `right of`0`, so`f(0) = 1# is a local maximum.

There are no other critical numbers, so there are no other local extrema.