How do you find the Maclaurin series of f(x)=cos(x^2) ? Calculus Power Series Constructing a Maclaurin Series 1 Answer Wataru Sep 12, 2014 We have the Maclaurin series cosx=sum_{n=0}^infty(-1)^n{x^{2n}}/{(2n)!} by replacing x by x^2, cos(x^2)=sum_{n=0}^infty(-1)^n{x^{4n}}/{(2n)!} Answer link Related questions How do you find the Maclaurin series of f(x)=(1-x)^-2 ? How do you find the Maclaurin series of f(x)=cosh(x) ? How do you find the Maclaurin series of f(x)=cos(x) ? How do you find the Maclaurin series of f(x)=e^(-2x) ? How do you find the Maclaurin series of f(x)=e^x ? How do you find the Maclaurin series of f(x)=ln(1+x) ? How do you find the Maclaurin series of f(x)=ln(1+x^2) ? How do you find the Maclaurin series of f(x)=sin(x) ? How do you use a Maclaurin series to find the derivative of a function? How do I obtain the Maclaurin series for f(x)= 2xln(1+x3)? See all questions in Constructing a Maclaurin Series Impact of this question 64537 views around the world You can reuse this answer Creative Commons License