Question

How do you find the magnitude and direction for U: magnitude 140, bearing 160° V: magnitude 200, bearing 290°?

Answer 1

`U=(-140 cos 20^o, 140 sin 20^o) = (-131.56, 47.883)` and
`V = (-200 cos 10^o, -200 sin 10^o) = (-196.96, -34.730)`.

Explanation:

If m is the magnitude and b is the bearing (with respect to x-axis),

the vector is `( m cos b, m sin b)`.

Here, `U = (140 cos 160^o, 140 sin 160^o)`

`=(-140 cos 20^o, 140 sin 20^o)`

`= (-131.56, 47.883)` and

`V =(299 cos 190^o, 200 sin 190^o)`

`= (-200 cos 10^o, -200 sin 10^o)`

`= (-196.96, -34.730)`.