How do you find the mean and median of 136, 129, 128, 122, 134, 120?

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Answer 1 · 2017-02-27T12:47:52

$Mean \approx 128.17 (2dp), Median= 128.5$ $"Mean"~~"128.17 (2dp), Median="128.5$ .

Recall that, $Mean= \sum \frac{x_{i}}{n},$ $"Mean="sumx_i/n,$

$= \frac{120 + 122 + 128 + 129 + 134 + 136}{6} = \frac{769}{6} \approx 128.17 (2 d p) .$ $={120+122+128+129+134+136}/6=769/6~~128.17 (2dp).$

To find the Median, let us arrange the data in ascending order :

$120, 122, 128, 129, 134, 136 .$ $120, 122, 128, 129, 134, 136.$

Hence, the Median is the observation situated at the Middle
Place.

As, we have, two such observations, namely, $128 and 129,$ $128" and "129,$ the

median will be their Average.

$:." Median="(128+129)/2=128.5$ .