How do you find the midpoint of [ 11/3, 11/2] and [4/3, 3/2]?

2 Answers
Mar 12, 2016

P_m={55/12,17/12}Pm={5512,1712}

Explanation:

P_1=[11/3,11/2]" "P_2=[4/3,3/2]P1=[113,112] P2=[43,32]
P_m:" Midpoint" Pm: Midpoint
P_"m x"=(P_"1 x"+P_"2 x")/2=(11/3+11/2)/2=((22+33)/6)/2=55/12Pm x=P1 x+P2 x2=113+1122=22+3362=5512
P_"m y"=(P_"1 y"+P_"2 y")/2=(4/3+3/2)/2=((8+9)/6)/2=17/12Pm y=P1 y+P2 y2=43+322=8+962=1712
P_m={55/12,17/12}Pm={5512,1712}

Mar 12, 2016

(5/2,7/2)(52,72)

Explanation:

To get the xx-coordinate of the midpoint, find the average of the xx-coordinates.
(11/3+4/3)/2=(15/3)/2=5/2113+432=1532=52
To get the yy-coordinate of the midpoint, find the average of the yy-coordinates.
(11/2+3/2)/2=(14/2)/2=7/2112+322=1422=72