How do you find the missing value to create a perfect square trinomial for $x^{2} + 8 x$ $x^2+8x$ ?

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How do you find the missing value to create a perfect square trinomial for $x^{2} + 8 x$ $x^2+8x$ ?

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Answer 1 · 2018-07-06T19:01:58

$+ 16$ $+16$

Explanation:

${(x + a)}^{2} = x^{2} + 2 a x + a^{2}$ $(x+a)^2=x^2+2ax+a^2$

$compare with x^{2} + 8 x$ $"compare with "x^2+8x$

$2 a = 8 \Rightarrow a = \frac{8}{2} = 4$ $2a=8rArra=8/2=4$

$hence x^{2} + 8 x + 4^{2} = x^{2} + 8 x + 16 = {(x + 4)}^{2}$ $"hence "x^2+8x+4^2=x^2+8xcolor(red)(+16)=(x+4)^2$

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How do you find the missing value to create a perfect square trinomial for $x^{2} + 8 x$ $x^2+8x$ ?

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Explanation:

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Science

Math

Humanities

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How do you find the missing value to create a perfect square trinomial for x2+8xx^2+8x?

1 Answer

Explanation:

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How do you find the missing value to create a perfect square trinomial for $x^{2} + 8 x$ $x^2+8x$ ?