How do you find the other two side of a right triangle ABC, if $∠B=60$ and $AB=12$ where AB is the hypotenuse?

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Answer 1 · 2014-11-06T11:26:13

$mathbf{30^circ"-"60^circ"-"90^circ}$ Triangle

The ratios of three sides of a $30^circ"-"60^circ"-"90^circ$ triangle are:

$1:sqrt{3}:2$

Since the posted Triangle ABC is a $30^circ"-"60^circ"-"90^circ$ triangle, we have the ratios:

$BC:AC:AB = 1:sqrt{3}:2$

$AB=12 => BC={AB}/2=12/2=6$

$AC=BC cdot sqrt{3}=6sqrt{3}$

Hence, $BC=6$ and $AC=6sqrt{3}$ .

I hope that this was helpful.

How do you find the other two side of a right triangle ABC, if ∠B=60∠B=60 and AB=12AB=12 where AB is the hypotenuse?