How do you find the perimeter if it's a triangle in a coordinate plane X(0,2), Y(4,-1), Z(-2,-1)?

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Answer 1 · 2018-05-12T04:31:34

$color(indigo)("Perimeter of the triangle XYZ " = 14.61 " sq units"$

$"Distance between two points, knowing their coordinates "$

$d = sqrt((x_2-x_1)^2 + (y_2 - y_1)^2)$

$X (0,2), Y (4,-1), Z(-2,-1)$

$bar (XY) = z = sqrt((4-0)^2 + (-1-2)^2) = 5$

$bar(YZ) = x = sqrt((-2-4)^2 + (-1+1)^2 = 6$

$bar(XZ) = y = sqrt((-2-0)^2 + (-1-2)^2) = 3.61$

$color(indigo)("Perimeter of the triangle XYZ " = z + x + y = 5 + 6 + 3.61 = 14.61 " sq units"$