How do you find the perimeter of a triangle given (2, 2), (-2, 2), and (-2, -3)?

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How do you find the perimeter of a triangle given (2, 2), (-2, 2), and (-2, -3)?

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Answer 1 · 2018-04-21T17:05:51

Perimeter is $15.4$ $15.4$

Explanation:

To find perimeter, we should find sum of all the three sides of the triangle formed by $A (2, 2)$ $A(2,2)$ , $B (- 2, 2)$ $B(-2,2)$ and $C (- 2, - 3)$ $C(-2,-3)$

Before we do that observe that between $A$ $A$ and $B$ $B$ , ordinate is same and hence line joining them is parallel to $x$ $x$ -axis. Further as difference between abscissa is $4$ $4$ , length of $A B$ $AB$ is $4$ $4$ .

Also observe that between $B$ $B$ and $C$ $C$ , abscissa is same and hence line joining them is parallel to $y$ $y$ -axis. Further as difference between ordinate is $5$ $5$ , length of $B C$ $BC$ is $5$ $5$ .

As $A B$ $AB$ is parallel to $x$ $x$ -axis and $B C$ $BC$ is parallel to $y$ $y$ -axis, $DeltaABC$ is right angled triangle and hence from Pythagoras theorem, hypotenuse $AC=sqrt(4^2+5^2)=sqrt(16+25)=sqrt41=6.403~=6.4$

and perimeter is $4+5+6.4=15.4$

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How do you find the perimeter of a triangle given (2, 2), (-2, 2), and (-2, -3)?

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