How do you find the perimeter of a triangle when the sides are $4, 12, and \sqrt{28}$ $4, 12, and sqrt28$ ?

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How do you find the perimeter of a triangle when the sides are $4, 12, and \sqrt{28}$ $4, 12, and sqrt28$ ?

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Answer 1 · 2018-04-24T04:36:41

You add them all. The answer is 16 + $2 \sqrt{7}$ $2sqrt(7)$

Explanation:

You factor out the $\sqrt{28}$ $sqrt(28)$ , and it becomes $2 \sqrt{7}$ $2sqrt(7)$ . With this, you add this to 4 and 12. You end up getting 16 + $2 \sqrt{7}$ $2sqrt(7)$ .

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How do you find the perimeter of a triangle when the sides are $4, 12, and \sqrt{28}$ $4, 12, and sqrt28$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you find the perimeter of a triangle when the sides are 4,12,and√284, 12, and sqrt28?

1 Answer

Explanation:

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Impact of this question

How do you find the perimeter of a triangle when the sides are $4, 12, and \sqrt{28}$ $4, 12, and sqrt28$ ?