How do you find the period and amplitude of $y=3sin10x$ ?

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Answer 1 · 2016-12-13T03:34:23

Please see the explanation.

Given the general form: $y = (A)sin(Bx + C) + D$

The amplitude is A
The period, $T = (2pi)/B$
The phase shift, $theta = -C/B$
The Vertical shift is D

For your problem, the amplitude is 3 and the period, $T = (2pi)/3$

How do you find the period and amplitude of y=3sin10xy=3sin10x?