Question

How do you find the period and amplitude of `y=5/2cos(x/2)`?

Answer 1

Amplitude = 5/2, Period `= **4pi**`

Explanation:

Use the form `a* cos(bx - c) + d`

Given equation is `y = (5/2) cos (x/2)`

In this equation
`a = 5/2, b = 1/2, c = 0, d = 0`

Amplitude = `a = 5/2`

Period `= (2pi)/b = (2pi) / (1/2) = 4pi`

Phase shift = c/b = 9

Vertical shift = d = 0
graph{(5/2) cos (x/2) [-10, 10, -5, 5]}