Question

How do you find the period of sin(3x)?

Answer 1

`sin 3x = sin (3x + 2pi) = sin [3(x + (2pi)/3)] = sin 3x`

This means "after the arc rotating three time of `(x + (2pi/3))`, sin 3x comes back to its initial value"
So, the period of sin 3x is `(2pi)/3.`