How do you find the period of sin(3x)?

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How do you find the period of sin(3x)?

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Answer 1 · 2015-05-21T13:55:37

$sin 3 x = sin (3 x + 2 π) = sin [3 (x + \frac{2 π}{3})] = sin 3 x$ $sin 3x = sin (3x + 2pi) = sin [3(x + (2pi)/3)] = sin 3x$

This means "after the arc rotating three time of $(x + (2 \frac{π}{3}))$ $(x + (2pi/3))$ , sin 3x comes back to its initial value"
So, the period of sin 3x is $\frac{2 π}{3} .$ $(2pi)/3.$

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How do you find the period of sin(3x)?

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