How do you find the period of $sin 5 π t$ $sin 5pit$ ?

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Answer 1 · 2016-04-24T05:16:40

$\frac{2}{5}$ $2/5$

The period P of f(t) is given by f(t+P) = f(t), for the least value of P.

The period of sin kt = $\frac{2 π}{k}$ $(2pi)/k$ .

Here, k = $5 π$ $5pi$ . So, the period - $\frac{2 π}{5 π} = \frac{2}{5}$ $(2pi)/(5pi)=2/5$ ..

How do you find the period of sin5πtsin 5pit?