Question

How do you find the period of `sin 5pit`?

Answer 1

`2/5`

Explanation:

The period P of f(t) is given by f(t+P) = f(t), for the least value of P.

The period of sin kt = `(2pi)/k`.

Here, k = `5pi`. So, the period - `(2pi)/(5pi)=2/5`..