How do you find the period of #y = 1 + 2sin [((pi x)/2) - (pi/4)]#?

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Answer 1 · 2016-12-07T03:47:57

Please see the explanation.

For a sine function of the general form:

#y = Asin(Bx + C) + D#

The period, #tau#, is found, using the equation:

#tau = (2pi)/B#

We observe that #B = pi/2# in the given equation:

#tau = (2pi)/(pi/2)#

#tau = 4#