How do you find the period of $y=1/2sin[(pix)/3]$ ?

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Answer 1 · 2018-04-05T13:04:08

$color(blue)(6)$

If we express the the sine function in the form:

$y=asin(bx+c)+d$

Where:

$bba \ \ \ \ \ ="amplitude"$

$bb((2pi)/b)="period"$

$bb((-c)/b)="phase shift"$

$\ \ \ \ bbd \ \ ="vertical shift"$

$y=1/2sin(pi/3x)$

$:.$

$b=pi/3$

Period is:

$(2pi)/b=(2pi)/(pi/3)=(6pi)/pi=color(blue)(6)$

The graph confirms this:

enter image source here

How do you find the period of y=1/2sin[(pix)/3]y=1/2sin[(pix)/3]?