How do you find the period of $y=2 tan(3pi(x) +4)$ ?

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Answer 1 · 2017-06-04T20:12:27

When given a function of the form:

$y = Atan(Bx + C) + D$

The period is $P = pi/B$

Given: $y=2 tan(3pi(x) +4)$

$P = pi/(3pi)$

$P = 1/3$

How do you find the period of y=2 tan(3pi(x) +4) y=2 tan(3pi(x) +4) ?