How do you find the period of $y=-3+2sin(1/4x-pi/8)$ ?

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Answer 1 · 2017-04-23T02:27:05

When given a sine function of the form $y = Asin(Bx-C)+D$ , the period, T, is:

$T = (2pi)/B$

To find, the period, T, for the given problem:

$T = (2pi)/(1/4)$

$T = 8pi$

How do you find the period of y=-3+2sin(1/4x-pi/8)y=-3+2sin(1/4x-pi/8)?