How do you find the period of $y = 3 + cos x$ $y=3+ cos x$ ?

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Answer 1 · 2016-05-08T04:45:20

$2 π$ $2pi$

The period of f(x) = a + b cos (cx + d) is $\frac{2 π}{c}$ $(2pi)/c$

$f (x + p e r i o d) = f (x + \frac{2 π}{c}) = a + b cos (c (x + \frac{2 π}{c}) + d)$ $f(x+ period) = f(x+(2pi)/c)=a+bcos(c(x+(2pi)/c)+d)$

$= a + b cos ((c x + d) + 2 π)$ $=a+bcos((cx+d)+2pi)$

$= a + b cos (c x + d)$ $=a+bcos(cx+d)$

$= f (x)$ $=f(x)$

Here, c = 1, and so, the period is $2 π$ $2pi$ ..

How do you find the period of y=3+ cos xy=3+cosxy=3+ cos x?