Question

How do you find the period of `y=3tan[2x-(pi/6)]`?

Answer 1

Refer to explanation

Explanation:

The graph of the function is

graph{3*tan(2x-pi/6) [-10, 10, -5, 5]}

The period for a function with formula
`y=a*tan(bx+c)` is `T=pi/b` hence in our
case `T=pi/2`