How do you find the period, phase and vertical shift of #y=4sec2(theta+pi/2)-3#?

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Answer 1 · 2018-05-31T16:05:11

As explained

Standard form of secant function is

#y = A sec (Bx - C) + D#

Guven : #y = 4 sec (2theta + pi) - 3#

Amplitude for secant function - None

Period #= pi / |B| = (2pi) / 2 = pi#

Phase Shift # = -C / B = -pi / 2, #pi/2# to the left

Vertical Shift #= D = -3#