How do you find the polar equation for $x^{2} = 12$ $x^2=12$ ?

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How do you find the polar equation for $x^{2} = 12$ $x^2=12$ ?

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Answer 1 · 2016-07-22T05:59:09

$r^{2} = 12 {sec}^{2} θ$ $r^2=12sec^2theta$

Explanation:

Relation between polar coordinates $(r, θ)$ $(r,theta)$ and rectangular coordinates is given by $x = r cos θ$ $x=rcostheta$ , $y = r sin θ$ $y=rsintheta$ , $r^{2} = x^{2} + y^{2}$ $r^2=x^2+y^2$ and $tan θ = \frac{y}{x}$ $tantheta=y/x$ .

Hence $x^{2} = 12$ $x^2=12$ can be written as $r^{2} {cos}^{2} θ = 12$ $r^2cos^2theta=12$

or $r^{2} = 12 {sec}^{2} θ$ $r^2=12sec^2theta$

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How do you find the polar equation for $x^{2} = 12$ $x^2=12$ ?

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