How do you find the polar equation for #x^2=12#? Trigonometry The Polar System Converting Between Systems 1 Answer Shwetank Mauria Jul 22, 2016 #r^2=12sec^2theta# Explanation: Relation between polar coordinates #(r,theta)# and rectangular coordinates is given by #x=rcostheta#, #y=rsintheta#, #r^2=x^2+y^2# and #tantheta=y/x#. Hence #x^2=12# can be written as #r^2cos^2theta=12# or #r^2=12sec^2theta# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1828 views around the world You can reuse this answer Creative Commons License