How do you find the polar equation for $x - 3 y = 1$ $x-3y=1$ ?

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Answer 1 · 2016-10-27T17:06:52

Please see the explanation.

Substitute $r cos (θ)$ $rcos(theta)$ for x and $r sin (θ)$ $rsin(theta)$ for y:

$r cos (θ) - 3 r sin (θ) = 1$ $rcos(theta) - 3rsin(theta) = 1$

Divide both sides by $cos (θ) - 3 sin (θ)$ $cos(theta) - 3sin(theta)$

$r = \frac{1}{cos (θ) - 3 sin (θ)}$ $r = 1/(cos(theta) - 3sin(theta))$

How do you find the polar equation for x-3y=1x−3y=1x-3y=1?