How do you find the polar equation of #xy=4#? Trigonometry The Polar System Converting Between Systems 1 Answer Bdub Mar 6, 2016 #rcostheta*rsintheta = 4 -> r^2 = 4 (1/sin theta)(1/costheta) = 4 csc theta sectheta# Explanation: Substitute in #r cos theta# for x and #rsin theta # for y then isolate #r^2#. If you want to solve for r you have to take the square root of both sides. Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 11015 views around the world You can reuse this answer Creative Commons License