How do you find the polar equation of $x y = 4$ $xy=4$ ?

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How do you find the polar equation of $x y = 4$ $xy=4$ ?

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Answer 1 · 2016-03-06T03:49:33

$r cos θ \cdot r sin θ = 4 \to r^{2} = 4 (\frac{1}{sin θ}) (\frac{1}{cos θ}) = 4 csc θ sec θ$ $rcostheta*rsintheta = 4 -> r^2 = 4 (1/sin theta)(1/costheta) = 4 csc theta sectheta$

Explanation:

Substitute in $r cos θ$ $r cos theta$ for x and $r sin θ$ $rsin theta$ for y then isolate $r^{2}$ $r^2$ . If you want to solve for r you have to take the square root of both sides.

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How do you find the polar equation of $x y = 4$ $xy=4$ ?

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How do you find the polar equation of $x y = 4$ $xy=4$ ?