Question

How do you find the product of `(4c+1)(2c+1)`?

Answer 1

`8 c^(2) + 6 c + 1`

Explanation:

We have: `(4 c + 1) (2 c + 1)`

Let's expand the parentheses:

`= (4 c) (2 c) + (4 c) (1) + (1) (2 c) + (1) (1)`

`= 8 c^(2) + 4 c + 2 c + 1`

`= 8 c^(2) + 6 c + 1`