How do you find the range of # f(x)=1/(x-3)#?
1 Answer
Jun 18, 2018
Explanation:
#"let "y=1/(x-3)#
#"rearrange making "x" the subject"#
#y(x-3)=1#
#xy-3y=1#
#x=(1+3y)/y#
#"the denominator "!=0#
#"range "y in(-oo,0)uu(0,oo)#
graph{1/(x-3) [-10, 10, -5, 5]}
