Question

How do you find the range of `f(x)=x^2-x-2`?

Answer 1

The range is `[-9/4,+oo)`

Explanation:

The domain is `R` and we have that

#y=(x^2-x+1/4)-2-1/4=>y=(x-1/2)^2-9/4=>y+9/4=(x-1/2)^2=> y+9/4>=0=>y>=-9/4#