How do you find the rectangular coordinates given the polar coordinates $(14, 130^{\circ})$ $(14, 130^circ)$ ?

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Answer 1 · 2016-11-08T20:00:56

The point is $(14 cos (130^{\circ}), 14 sin (130^{\circ})) \approx (- 8.99, 10.72)$ $(14cos(130^@),14sin(130^@))~~ (-8.99, 10.72)$

$x = r cos (θ) and y = r sin (θ)$ $x = rcos(theta) and y = rsin(theta)$

$x = 14 cos (130^{\circ}) and y = 14 sin (130^{\circ})$ $x = 14cos(130^@) and y = 14sin(130^@)$

The point is $(14 cos (130^{\circ}), 14 sin (130^{\circ})) \approx (- 8.99, 10.72)$ $(14cos(130^@),14sin(130^@))~~ (-8.99, 10.72)$

How do you find the rectangular coordinates given the polar coordinates (14, 130^circ)(14,130∘)(14, 130^circ)?