How do you find the rectangular form of $(4, - \frac{π}{2})$ $(4, -pi/2)$ ?

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How do you find the rectangular form of $(4, - \frac{π}{2})$ $(4, -pi/2)$ ?

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Answer 1 · 2018-05-25T04:28:06

$(0, - 4)$ $(0, -4)$

Explanation:

Polar coordinates are represented as:

$(r, θ)$ $(r, theta)$

Since we're given:

$(4, - \frac{π}{2})$ $(4, -pi/2)$

$4$ $4$ is $r$ $r$ and $- \frac{π}{2}$ $-pi/2$ is $θ$ $theta$

Use the formula:

$(r cos θ, r sin θ)$ $(rcostheta, rsintheta)$

The rest is plugging and solving:

$r cos θ$ $rcostheta$
$4 cos (- \frac{π}{2})$ $4cos(-pi/2)$
$4 (0)$ $4(0)$ $The cos value of - \frac{π}{2} is 0$ $color(blue)(" The "cos " value of "-pi/2" is 0")$
$0$ $0$
$x = 0$ $x=0$

$r sin θ$ $rsintheta$
$4 sin (- \frac{π}{2})$ $4sin(-pi/2)$
$4 (- 1)$ $4(-1)$ $The sin value of - \frac{π}{2} is -1$ $color(blue)(" The "sin " value of "-pi/2" is -1")$
$- 4$ $-4$
$y = - 4$ $y=-4$

$(0, - 4)$ $color(red)((0, -4)$

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How do you find the rectangular form of $(4, - \frac{π}{2})$ $(4, -pi/2)$ ?

1 Answer

Explanation:

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How do you find the rectangular form of $(4, - \frac{π}{2})$ $(4, -pi/2)$ ?