How do you find the remainder for $(x^3+6x^2-4x+2)div(x+1)$ ?

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Answer 1 · 2016-11-02T15:37:32

Use the Remainder Theorem . The remainder is 11

The Remainder Theorm states that:

Given a polynomial, $p(x)$ , the remainder, $r(a)$ , of the division, $p(x) -: (x - a)$ , is equal to the polynomial evaluated at a:

$r(a) = p(a)$

$(x + 1) = (x - -1)$ , therefore, $a = -1$

Evaluate the polynomial at -1:

$(-1)^3 + 6(-1)^2 - 4(-1) + 2 = 11$

The remainder is 11.

How do you find the remainder for (x^3+6x^2-4x+2)div(x+1)(x^3+6x^2-4x+2)div(x+1)?