How do you find the remainder for $(x^{3} + x^{2} - 12 x - 13) \div (x - 2)$ $(x^3+x^2-12x-13)div(x-2)$ ?

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How do you find the remainder for $(x^{3} + x^{2} - 12 x - 13) \div (x - 2)$ $(x^3+x^2-12x-13)div(x-2)$ ?

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Answer 1 · 2016-09-15T18:32:58

By the Remainder Theorem, the Remainder is the value of the Dividend Poly. at $x = 2, i . e .,$ $x=2, i.e.,$
The Remainder $= 2^{3} + 2^{2} - 12 \cdot 2 - 13 = 8 + 4 - 24 - 13 = - 25 .$ $=2^3+2^2-12*2-13=8+4-24-13=-25.$

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How do you find the remainder for $(x^{3} + x^{2} - 12 x - 13) \div (x - 2)$ $(x^3+x^2-12x-13)div(x-2)$ ?

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How do you find the remainder for (x3+x2−12x−13)÷(x−2)(x^3+x^2-12x-13)div(x-2)?

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How do you find the remainder for $(x^{3} + x^{2} - 12 x - 13) \div (x - 2)$ $(x^3+x^2-12x-13)div(x-2)$ ?