How do you find the remainder when $x^3-7x^2+14x-8$ is divided by x+1?

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Answer 1 · 2016-10-30T08:04:26

The remainder is $=-30$

Let $f(x)=x^3-7x^2+14x-8$
Then we calculate
$f(-1)=(-1)^3-7*(-1)^2+14(-1)-8=-30$
So the remainder is $=-30$

You can also do a long division

How do you find the remainder when x^3-7x^2+14x-8x^3-7x^2+14x-8 is divided by x+1?