How do you find the remainder when $x^3+8x^2+11x-20$ is divided by x-5?

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Answer 1 · 2016-09-17T13:04:27

When $x^3+8x^2+11x-20$ is divided by $(x-5)$ , the remainder is $360$

According remainder theorem, if a polynomial $f(x)$ is divided by a binomial of degree $1$ i.e. $(x-a)$ , the remainder is $f(a)$ .

Hence, when $x^3+8x^2+11x-20$ is divided by $(x-5)$ , the remainder is

$f(5)=5^3+8xx5^2+11xx5-20$

= $125+8xx25+55-20$

= $125+200+55-20$

= $360$

How do you find the remainder when x^3+8x^2+11x-20x^3+8x^2+11x-20 is divided by x-5?