Question

How do you find the remaining trigonometric functions of `theta` given `sintheta=-20/29` and `theta` terminates in QIII?

Answer 1

`cos^2 t = 1 - sin^2 t = 1 - 400/841 = 441/841`
`cos t = +- 21/29`
Since t is in Quadrant 3, cos t is negative.
`cos t = - 21/19`
`tan t = sin/(cos) = (-20/29)(-29/21) = 20/21`
`cot t = 1/(tan) = 21/20`
`sec t = 1/(cos) = - 19/21`
`csc t = 1/(sin) = - 29/20`