How do you find the second derivative of $f (t) = t^{3} - 4 t^{2}$ $f(t)=t^3-4t^2$ ?

Question

2494 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-01T19:44:35

$\frac{d^{2} f}{{d t}^{2}} = 6 t - 8$ $(d^2f)/dt^2 = 6t - 8$

The power rule states that $(x^n)' = nx^(n-1)$ . We can use it to find the first derivative:

$(df)/(dt) = 3t^2 - 8t$

We can use the power rule again to find the second derivative.

$(d^2f)/(dt^2) = 6t - 8$ .

How do you find the second derivative of f(t)=t^3-4t^2f(t)=t3−4t2f(t)=t^3-4t^2?