Question

How do you find the second derivative of `f(x)=3x^-2`?

Answer 1

`d^2/(dx^2) 3x^(-2) =18x^-4`

Explanation:

Using the power rule:

`d/(dx) 3x^(-2) = (-2)*3x^(-2-1) = -6x^(-3)`

`d^2/(dx^2) 3x^(-2) = d/(dx) -6x^-3 = (-3)*(-6)x^(-3-1) =18x^-4`