How do you find the second derivative of $sin(2x)$ ?

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Answer 1 · 2017-04-13T21:08:45

$f''(x)=-4sin 2x$

Let $f(x)=sin 2x$ .

By $(sin x)'=cos x$ and Chain Rule,

$f'(x)=cos 2x cdot(2x)'=2cos 2x$

By $(cos x)'=-sin x$ and Chain Rule,

$f''(x)=-2sin 2x cdot (2x)'=-4sin 2x$

I hope that this was clear.

How do you find the second derivative of sin(2x)sin(2x)?