How do you find the slant asymptote of $\frac{2 x - 4}{x^{2} - 4}$ $(2x-4)/(x^2-4)$ ?

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Answer 1 · 2015-11-27T18:16:48

There is no slant asymptote if the polynomial in the denominator is a higher degree compared to the polynomial in the numerator.

Since $x^{2}$ $x^2$ is a higher degree compared to $2 x$ $2x$ , there is no slant asymptote.

There is a horizontal asymptote at $y = 0$ $y=0$ and two vertical asymptotes at $x = \pm 2$ $x=+-2$

hope that helps

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How do you find the slant asymptote of (2x-4)/(x^2-4)2x−4x2−4(2x-4)/(x^2-4)?