How do you find the slant asymptote of #{-9 x^3 - 9 x^2 + 28 x + 9 }/{3 x^2 + 6 x + 2}#?
1 Answer
Jul 29, 2016
Explanation:
We can long divide the coefficients like this:
to find that:
#(-9x^3-9x^2+28x+9)/(3x^2+6x+2) = -3x+3+(16x+3)/(3x^2+6x+2)#
So the slant asymptote is:
#y = -3x+3#
