How do you find the slant asymptote of $a (x) = \frac{2 x^{2} - 1}{3 x^{3} - 2 x + 1}$ $a(x)=(2x^2-1) / (3x^3-2x+1)$ ?

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Answer 1 · 2017-07-29T05:28:54

There is no slant asymptote.

The degree of the numerator is $= 2$ $=2$

The degree of the denominator is $= 3$ $=3$

Therefore,

As the degree of the numerator is $<$ $<$ than the degree of the denominator, there is no slant asymptote

graph{(2x^2-1)/(3x^3-2x+1) [-10, 10, -5, 5]}

How do you find the slant asymptote of a(x)=(2x^2-1) / (3x^3-2x+1)a(x)=2x2−13x3−2x+1 a(x)=(2x^2-1) / (3x^3-2x+1)?