How do you find the slant asymptote of f(x)=( 21 x^2 ) / ( 3 x + 7)f(x)=21x23x+7?

1 Answer
Jul 6, 2016

y = 7xy=7x

Explanation:

f(x)=( 21 x^2 ) / ( 3 x + 7)f(x)=21x23x+7

you ask specifically about slants wcih means we consider x to pm oox±

lim_{x to pm oo} ( 21 x^2 ) / ( 3 x + 7)

= lim_{x to pm oo} ( 21 x ) / ( 3 + 7/x)

and lim_{x to pm oo} ( 3 + 7/x) = 3

so we can identify y = 21/3 x = 7x as a slant asymptote